Quantitative Aptitude · Numbers & Simplification
Problems on Numbers — Questions & Answers
These are word problems that turn a description of one or more unknown numbers into equations: sums and differences, digit reversal, consecutive integers, and ratios. The skill is translating each sentence faithfully.
- 5 solved questions
- Step-by-step AI walkthroughs
- Key formulas included
Key formulas
A two-digit number with tens digit t and units digit u is 10t+u; reversing gives 10u+t
Difference between a two-digit number and its reverse is 9(t−u)
Three consecutive integers: n−1,n,n+1 — their sum is 3n
5 solved Problems on Numbers questions
The sum of two numbers is 40 and their difference is 8. What is the larger number?
Solution — answer A
The larger number is 240+8=24 (and the smaller is 240−8=16).
4 steps · reveal one at a timeStep 1: Understand the problem
We are given two pieces of information about two numbers: their sum is 40 and their difference is 8. Our goal is to find the value of the larger of these two numbers.
Step 2: Apply the formula
To find the larger number when you know both the sum and the difference of two numbers, you can use the formula: Larger Number=(Sum+Difference)/2.
Step 3: Calculate the larger number
Substitute the given values into the formula: Larger Number=(40+8)/2. First, calculate the sum: 40+8=48. Then, divide by 2: 48/2=24.
Step 4: The answer
So the answer is (A) 24. The larger number is 24, because (24+16=40) and (24−16=8), which matches the given conditions.
A number is as much greater than 31 as it is less than 75. Find the number.
Solution — answer C
The number is the midpoint of 31 and 75: 231+75=53.
5 steps · reveal one at a timeStep 1: Understand the relationship
The problem states that a number is 'as much greater than 31 as it is less than 75'. This means the number is exactly halfway between 31 and 75.
Step 2: Identify the method
To find a number that is exactly halfway between two other numbers, we need to calculate their average or midpoint. This is done by adding the two numbers and dividing by 2.
Step 3: Calculate the midpoint
We need to find the average of 31 and 75. The formula for the midpoint is 2Number 1+Number 2. So, we calculate 231+75.
Step 4: Perform the calculation
First, add 31 and 75: 31+75=106. Then, divide the sum by 2: 106÷2=53. The number is 53.
Step 5: The answer
So the answer is (C) 53. This number is 53−31=22 greater than 31, and 75−53=22 less than 75, confirming it's the correct midpoint.
The sum of three consecutive even numbers is 234. What is the smallest of them?
Solution — answer A
Three consecutive even numbers average to the middle one: 234÷3=78. So the numbers are 76, 78 and 80, and the smallest is 76.
4 steps · reveal one at a timeStep 1: Find the Middle Number
For any set of consecutive numbers, including consecutive even numbers, their average is always the middle number. To find the average, divide the sum by the count of numbers. Here, we have 3 numbers.
Step 2: Calculate the Middle Number
The sum of the three consecutive even numbers is 234. Since there are 3 numbers, the middle number is 234÷3=78. This means 78 is the second of the three numbers.
Step 3: Identify the Smallest Number
Since 78 is the middle even number, the even number immediately before it is 78−2=76. The even number immediately after it is 78+2=80. So the three numbers are 76, 78, and 80.
Step 4: The answer
So the answer is (A) 76. From the set of numbers 76, 78, and 80, the smallest number is 76.
A two-digit number equals 4 times the sum of its digits. When 18 is added to the number, its digits are reversed. Find the number.
Solution — answer C
Let the number be 10t+u. '4 times the digit sum' gives 10t+u=4(t+u), i.e. u=2t. Adding 18 reverses the digits: 9t+18=9u, so u−t=2. Then 2t−t=2 gives t=2, u=4 and the number 24.
5 steps · reveal one at a timeStep 1: Set up the number
Let's represent the two-digit number using its tens digit t and units digit u. So, the number can be written as 10t+u. Remember, t and u are single digits.
Step 2: Apply the first rule
The question states the number equals 4 times the sum of its digits. We can write this as an equation: 10t+u=4(t+u). Simplifying this gives us 10t+u=4t+4u, which further simplifies to 6t=3u, or u=2t.
Step 3: Apply the second rule
Next, we know that when 18 is added to the number, its digits are reversed. The reversed number is 10u+t. So, (10t+u)+18=10u+t. Rearranging this equation gives 18=9u−9t, which simplifies to 2=u−t.
Step 4: Solve for the digits
Now we have two simple equations: u=2t and u−t=2. Substitute the first equation into the second: (2t)−t=2. This gives t=2. Then, substitute t=2 back into u=2t to find u=4. The digits are t=2 and u=4.
Step 5: The answer
So the answer is (C) 24. The number is 10t+u=10(2)+4=24. This number satisfies both conditions: 24=4(2+4) and 24+18=42 (digits reversed).
If the numerator of a fraction is increased by 20% and the denominator decreased by 10%, the fraction becomes 2116. What was the original fraction?
Solution — answer C
If the fraction is ba, then 0.9b1.2a=ba×34=2116. So ba=2116×43=74.
5 steps · reveal one at a timeStep 1: Set up the equation
Let the original fraction be ba. Increasing the numerator by 20% makes it 1.2a. Decreasing the denominator by 10% makes it 0.9b. The new fraction is 0.9b1.2a, which equals 2116.
Step 2: Simplify the expression
We can rewrite the new fraction as 0.91.2×ba. Simplifying the ratio 0.91.2 gives us 912, which reduces to 34. So, we have 34×ba=2116.
Step 3: Solve for original fraction
To find the original fraction ba, we need to isolate it. Divide both sides of the equation by 34. This means multiplying by its reciprocal, 43. So, ba=2116×43.
Step 4: Calculate the result
Now, perform the multiplication: 2116×43. We can simplify by canceling common factors. 16 divided by 4 is 4, and 21 divided by 3 is 7. This leaves us with 74.
Step 5: The answer
So the answer is (C) 74. This matches our calculated original fraction after reversing the percentage changes.
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