Quantitative Aptitude · Geometry & Mensuration
Surface Areas and Volume — Questions & Answers
These questions use the solid-geometry formulas for cuboids, cylinders, cones and spheres. 'Melting and recasting' keeps volume constant, which gives one equation linking the two shapes.
- 5 solved questions
- Step-by-step AI walkthroughs
- Key formulas included
Key formulas
Cuboid: volume lbh, surface area 2(lb+bh+hl)
Cylinder: volume πr2h, curved surface 2πrh
Cone: volume 31πr2h, curved surface πrl. Sphere: volume 34πr3, surface 4πr2
5 solved Surface Areas and Volume questions
What is the volume of a cuboid measuring 8 cm × 5 cm × 3 cm?
Solution — answer B
Volume =8×5×3=120 cm³.
4 steps · reveal one at a timeStep 1: Understand the Question
We need to find the volume of a cuboid. The question provides the three dimensions: length, width, and height.
Step 2: Recall Volume Formula
The formula for the volume of a cuboid is length × width × height. This calculates the total space it occupies.
Step 3: Calculate the Volume
Substitute the given dimensions into the formula. Volume =8 cm×5 cm×3 cm.
Step 4: The answer
So the answer is (B) 120 cm³ because multiplying the dimensions 8×5×3 gives 120, and the units are cubic centimeters.
Find the surface area of a sphere of radius 7 cm. (Take π=722.)
Solution — answer D
Surface area =4πr2=4×722×49=616 cm².
5 steps · reveal one at a timeStep 1: Recall the formula
To find the surface area of a sphere, we use the formula A=4πr2, where r represents the radius of the sphere. This is a standard formula you should remember for geometry problems.
Step 2: Note the given values
The question provides us with the radius of the sphere, r=7 cm. It also specifies that we should use the approximation π=722 for our calculation. These are all the values we need.
Step 3: Substitute and calculate
Now, substitute the given values into the formula: A=4×722×(7)2. First, calculate the square of the radius: (7)2=49. So the expression becomes A=4×722×49.
Step 4: Simplify and find area
We can simplify the calculation by cancelling out the 7 in the denominator with one of the 7s from 49. This gives A=4×22×7. Multiplying these numbers: 4×22=88, and 88×7=616. The surface area is 616 cm2.
Step 5: The answer
So the answer is (D) 616 cm². This matches our calculated surface area for the sphere with a radius of 7 cm.
A cylinder has radius 7 cm and height 10 cm. Find its curved surface area. (Take π=722.)
Solution — answer C
Curved surface area =2πrh=2×722×7×10=440 cm².
4 steps · reveal one at a timeStep 1: Identify Given Values
First, let's note the information given in the question. We have the radius r=7 cm and the height h=10 cm. We are also told to use π=722.
Step 2: Recall the Formula
The formula for the curved surface area of a cylinder is 2πrh. This formula calculates the area of the side of the cylinder, excluding the top and bottom circular faces.
Step 3: Calculate the Area
Now, substitute the given values into the formula: Curved surface area =2×722×7×10. We can simplify by cancelling out the 7s.
Step 4: The Answer
So the answer is (C) 440 cm². Performing the multiplication, 2×22×10=44×10=440. The curved surface area is 440 cm².
A solid metal sphere of radius 3 cm is melted and recast into small spheres of radius 1 cm. How many small spheres are formed?
Solution — answer B
Volume scales with the cube of the radius, so the number of small spheres is (13)3=27.
4 steps · reveal one at a timeStep 1: Understand the Goal
We are melting a large sphere and recasting its metal into many smaller spheres. The total volume of metal must remain the same throughout this process.
Step 2: Recall Volume Scaling
The volume of a sphere is proportional to the cube of its radius. This means if the radius changes by a factor, the volume changes by that factor cubed. The formula is V=34πr3.
Step 3: Calculate Volume Ratio
The large sphere has a radius of 3 cm, and the small spheres have a radius of 1 cm. The ratio of the radii is 13=3. Therefore, the ratio of their volumes is (13)3.
Step 4: The answer
So the answer is (B) 27. The volume of the large sphere is 33=27 times greater than the volume of one small sphere, meaning 27 small spheres can be formed.
A cone of height 24 cm and base radius 7 cm is melted and recast into a cylinder of base radius 7 cm. What is the height of the cylinder?
Solution — answer C
The cone's volume is 31πr2h=31π(49)(24)=π(49)(8). Equating to π(49)H gives H=8 cm.
5 steps · reveal one at a timeStep 1: Volume remains constant
When a 3D object is melted and recast into another shape, its volume stays the same. So, the volume of the original cone will be equal to the volume of the new cylinder.
Step 2: Calculate cone's volume
First, let's find the volume of the cone. The formula for the volume of a cone is Vc=31πr2h. With a radius of 7 cm and height of 24 cm, we get Vc=31π(72)(24)=31π(49)(24)=π(49)(8) cubic cm.
Step 3: Set up cylinder's volume
Now, let's consider the cylinder. Its base radius is also 7 cm. The formula for the volume of a cylinder is Vcyl=πr2H. So, Vcyl=π(72)H=π(49)H, where H is the unknown height of the cylinder.
Step 4: Equate volumes and solve
Since the volumes are equal, we can set them up: π(49)(8)=π(49)H. We can cancel out π(49) from both sides, which leaves us with H=8 cm.
Step 5: The answer
So the answer is (C) 8 cm. The height of the cylinder is 8 cm, as its volume must match the cone's volume.
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